s
种原料的试验范围是单纯形1
) 给定s和n,根据附录的使用表查到生成向量2
) 对每个i,计算![]()
3
) 计算![]()
(4.2)
由
就给出了对应
(4.3)
表26 No. |
C 1 |
C 2 |
X 1 |
X 2 |
X 3 |
1 |
1/22 |
13/22 |
0.787 |
0.087 |
0.126 |
2 |
3/22 |
5/33 |
0.631 |
0.285 |
0.084 |
3 |
5/22 |
19/22 |
0.523 |
0.065 |
0.412 |
4 |
7/22 |
11/22 |
0.436 |
0.282 |
0.282 |
5 |
9/22 |
3/33 |
0.360 |
0.552 |
0.087 |
6 |
11/22 |
17/22 |
0.293 |
0.161 |
0.546 |
7 |
13/22 |
9/22 |
0.231 |
0.454 |
0.314 |
8 |
15/22 |
1/22 |
0.174 |
0.788 |
0.038 |
9 |
17/22 |
15/22 |
0.121 |
0.280 |
0.599 |
10 |
19/22 |
7/22 |
0.071 |
0.634 |
0.296 |
11 |
21/22 |
21/22 |
0.023 |
0.044 |
0.993 |
公式(4.2)可以用递推方法以节省计算量,其算法如下:
(a)
令(b)
递推计算(c)
计算则
即为所求,用这个算法便于写计算程序。
相应的
R=0.90,No. |
x1 |
x2 |
Y |
1 |
0.817 |
0.055 |
8.508 |
2 |
0.684 |
0.179 |
9.464 |
3 |
0.592 |
0.340 |
9.935 |
4 |
0.517 |
0.048 |
9.400 |
5 |
0.452 |
0.210 |
10.680 |
6 |
0.394 |
0.384 |
9.748 |
7 |
0.342 |
0.592 |
9.698 |
8 |
0.293 |
0.118 |
10.238 |
9 |
0.247 |
0.326 |
9.809 |
10 |
0.204 |
0.557 |
9.732 |
11 |
0.163 |
0.809 |
8.933 |
12 |
0.124 |
0.204 |
9.971 |
13 |
0.087 |
0.456 |
9.881 |
14 |
0.051 |
0.727 |
8.892 |
15 |
0.017 |
0.033 |
10.139 |